(x-5)^2=2x^2-21x+53

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Solution for (x-5)^2=2x^2-21x+53 equation: 



(x-5)^2=2x^2-21x+53

We move all terms to the left:

(x-5)^2-(2x^2-21x+53)=0

We get rid of parentheses

-2x^2+(x-5)^2+21x-53=0

We add all the numbers together, and all the variables

-2x^2+21x+(x-5)^2-53=0

We move all terms containing x to the left, all other terms to the right

-2x^2+21x+(x-5)^2=53

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